x^2-14x+50=50

Solution for x^2-14x+50=50 equation:

x^2-14x+50=50

We move all terms to the left:

x^2-14x+50-(50)=0

We add all the numbers together, and all the variables

x^2-14x=0

a = 1; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·1·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*1}=\frac{28}{2}
=14
$